Physics, asked by srinusundaraneedi94, 29 days ago

7. A wheel rotating at an angular speed of 40 rads' is brought to rest by a constant torque in 5seclf the Nis 0.3 kg m", the work
done infrst 3s is
0 105.6)
(2) 100)
(3) 20)
(4) 703
B A cyinder is released from rest from the top of an incine of inclination and length"C. If the cylinder roles without slippling its
the bottom​

Answers

Answered by tanishq7880
0

Answer:

okkkkkkkkkkkkkkkkkk

Attachments:
Answered by VaibhavSR
0

Answer:

105.6

Explanation:

Angular accelerationα=40/5=8

Torque=Iα=8*0.3=2.4

Angular displacement in first 3secs

Work done=Torque×angular displacement

#SPJ3

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