Question

7. A wire is (7x-2) metres long. A length of (7+4x) metres is cut for use. Now, answer
the following questions:
(A) How much wire is left?
(B) If this left out wire is used for making an equilateral triangle, what is the length
of each side of the triangle so formed?​

Answer 1

Given: A wire is (7x-2) metres long. A length of (7+4x) metres is cut for use.

To find: (A) How much wire is left?  

             (B) If this left out wire is used for making an equilateral triangle, what is the length  of each side of the triangle so formed?​

Solution:

• So as per the question, a wire is (7x-2) metres long. A length of (7+4x) metres is cut for use.

• Answer (A):

• The wire left will be:

                 (7x-2) -  (7+4x)

                 7x - 2 - 7 - 4x

                 3x - 9

• Answer (B):

• Yes, the left out wire can make an equilateral triangle.

                 3x - 9 / 3

                 x - 3

Answer:

           So left out wire is 3x-9 and side of equilateral triangle is x-3.