Question

7 ab/c=cc

Plsss solve this question

Answer 1

A, B, C are digits.

7AB = 700+ 10 A + B.   Its value is between 700 and 799.

CC = 10 C + C = 11 C,      C * CC = 11*C²

Given   700+ 10 A + B = 11 C²

            So   700 <= 11 C² <= 799

                    63 <= C² <= 72

                    Hence,  C = 8.

So   11 C² = 11 * 8² = 704

Hence, B = 4,  A = 0.

A =0, B = 4, C = 8

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