Question

7. Δ ABC and Δ D BC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that Δ ABD ~= Δ ACD​

Answer 1

Answer:

AP is perpendicular to BC

so,

by comparing triangle ABD and ACD

angle BAD=angle DAC-------(1)

AD=AD-----------------------------(2)

angleABD=angleACD--------(3)

by equation 1,2,3 triangleABD~=ACD