Math, asked by vk2321541, 7 months ago

7. Add the sum of (-57) and (-13) to the sum of
(-110) and 46.
8. Subtract the sum of (-23) and 54 from the sum
of (-11),(-13) and (-21).
9. The product of three integers is (-110). If two
of the integers are 11 and (-5), find the third
integer.
10. Divide (-1000) by (-50) and to the quotient
add the product of (-13) and (-7).​

Answers

Answered by babithageorge2000
2

Step-by-step explanation:

7. -57 + -13 = -70

-110 + 46 = 64

-70 + 64 = -6

8. -11 + -13 + -21 = -24 + -21 = -45

-23 + 54 = +31

-45 - (31) = - 76

9. 11 × -5 × x = -110

-55 x = -110

x = -110/-55 = 2

10. -1000÷ -50 = + 20

-13 × -7 = +91

+20 + 91 = 111

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