7. Add the sum of (-57) and (-13) to the sum of
(-110) and 46.
8. Subtract the sum of (-23) and 54 from the sum
of (-11),(-13) and (-21).
9. The product of three integers is (-110). If two
of the integers are 11 and (-5), find the third
integer.
10. Divide (-1000) by (-50) and to the quotient
add the product of (-13) and (-7).
Answers
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Step-by-step explanation:
7. -57 + -13 = -70
-110 + 46 = 64
-70 + 64 = -6
8. -11 + -13 + -21 = -24 + -21 = -45
-23 + 54 = +31
-45 - (31) = - 76
9. 11 × -5 × x = -110
-55 x = -110
x = -110/-55 = 2
10. -1000÷ -50 = + 20
-13 × -7 = +91
+20 + 91 = 111
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