7. An aircraft flies 400 km from a point O on a bearing of 025°
and then 700 km on a bearing of 080° to arrive at B
a) How far north of O is B?
b) How far east of O is B?
c) Find the distance and bearing of B from O.
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Answered by
2
Answer:
Step-by-step explanation:
Applying cosine law to OAB with A being the point where the aircraft changes its bearing to 080
OB = sqrt[400^2 + 700^2 - 2*400*700*cos(125)] = 985.5 and by law of sines
sin(AOB)/700 = sin(125)/OB => angle AOB = asin[sin(125)*700/985.5] =35.5803
The bearing of B from O is 25 + 35.5803 = 60.5803 degrees and OB = 985.5 km.
Answered by
1
Answer:
Bearing is the angle in degrees (clockwise) between North and the direction to the destination or navigation aid. Relative bearing is the angle in degrees (clockwise) between the heading of the aircraft and the destination or navigation aid.
Step-by-step explanation:
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