7. An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts
from 10 m above the ground level, how long will it take to reach - 350 m.
Answers
Answered by
14
Answer:
It will take 1hr to reach
tanishk37:
please explain
how it came and thank you
if you will explain i will mark your answer as brainilist answer
ok i am explaining
350+10=360. speed =6m/min. speed =distance by time =360 by 6 min =60 min=1hr.
hope it helps you
Answered by
25
Answer:
Considering the elevator to be at constant speed and the destination to be 350 m below ground level,
The elevator has to travel 10m till the ground, then 350 m more.
So, the total distance to travel is 360 m
If the elevator's speed is 6 metres/minute,
Then
Time= Distance/Speed
= 360/6
=60 minutes
=1 hour
Thus the elevator would take 1 hour to reach its destination.
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