Question

7. An elevator descends into a mine shaft at the rate of 6 m/min. If the descend
starts from 10 m above the ground level, how long will it take to reach the shaft
350 m below the ground level?
​

Answer 1

Answer:

1 Hr.

Step-by-step explanation:

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,

The elevator has to travel 10m till the ground, then 350 m more.

So, the total distance to travel is 360 m

If the elevator's speed is 6 metres/minute,

Then

Time = Distance/Speed

       = 360/6

       = 60 minutes

       = 1 hour

Thus the elevator would take 1 hour to reach its destination.

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