Question

7. An elevator descends into a mine shaft at
the rate of 6 m/min. If the descent starts
from 12 m below the ground level, how
long will it take to reach -330 m.
​

Answer 1

Answer:

60 minutes

Step-by-step explanation:

Distance descended is denoted by a negative integer,

Initial height =+10 m

Final Depth =−350 m

Total distance to be descended by the elevator =(−350)−(+10)=−360 m

Given, the time is taken by the elevator to descend −6 m=1 minute

Thus, time taken by the elevator to descend −360 m=

(−6)

(−360)

------- [from the formula : speed=

time

distance

]

=60 minutes

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