7. An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts
from 10 m above the ground level, how long will it take to reach - 350 m.
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Answer:
an elevator decsends@6m/min
starting position=+10m
final position=-350m
total distance covered=10-(-350)m
=360m
gence, time taken =360/6
=60min
=1hr
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in 1 min
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