Question

7. An elevator descends into a mine shaft
at the rate of 6 m/min. If it begins
to descend from 20 m above the
ground, what will be its position after
45 minutes?​

Answer 1

Answer:

Step-by-step explanation:

6 x 45 = 270m

But we know that the elevator starts 20m above ground, so

270m - 20m = 250m

Therefore it travels 250m below ground in 45 m