Question

7. An elevator is falling freely. A person inside the elevator takes a coin out and releases it from rest. What will he
observe?

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Answer 1

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Let acceleration of lift be a.

Let acceleration of lift be a.acceleration of ball with respect to the lift = acceleration of ball with respesct to ground - acceleration of the lift

Let acceleration of lift be a.acceleration of ball with respect to the lift = acceleration of ball with respesct to ground - acceleration of the liftOr, aball(lift) = g - a = 9.8 m/s^2 - a = 32 ft./s^2 - a [ 9.8m = 32 ft. ]

Let acceleration of lift be a.acceleration of ball with respect to the lift = acceleration of ball with respesct to ground - acceleration of the liftOr, aball(lift) = g - a = 9.8 m/s^2 - a = 32 ft./s^2 - a [ 9.8m = 32 ft. ]displacement s = 6 ft.

Let acceleration of lift be a.acceleration of ball with respect to the lift = acceleration of ball with respesct to ground - acceleration of the liftOr, aball(lift) = g - a = 9.8 m/s^2 - a = 32 ft./s^2 - a [ 9.8m = 32 ft. ]displacement s = 6 ft.time taken t = 1 s.

Let acceleration of lift be a.acceleration of ball with respect to the lift = acceleration of ball with respesct to ground - acceleration of the liftOr, aball(lift) = g - a = 9.8 m/s^2 - a = 32 ft./s^2 - a [ 9.8m = 32 ft. ]displacement s = 6 ft.time taken t = 1 s.initial velocity u = 0

Let acceleration of lift be a.acceleration of ball with respect to the lift = acceleration of ball with respesct to ground - acceleration of the liftOr, aball(lift) = g - a = 9.8 m/s^2 - a = 32 ft./s^2 - a [ 9.8m = 32 ft. ]displacement s = 6 ft.time taken t = 1 s.initial velocity u = 0s = ut + 1/2 at^2 = 0*1 + 1/2 (32-a)*1*1 = 1/2 (32-a)

Let acceleration of lift be a.acceleration of ball with respect to the lift = acceleration of ball with respesct to ground - acceleration of the liftOr, aball(lift) = g - a = 9.8 m/s^2 - a = 32 ft./s^2 - a [ 9.8m = 32 ft. ]displacement s = 6 ft.time taken t = 1 s.initial velocity u = 0s = ut + 1/2 at^2 = 0*1 + 1/2 (32-a)*1*1 = 1/2 (32-a)Therefore, 6 = 1/2 (32-a)

Let acceleration of lift be a.acceleration of ball with respect to the lift = acceleration of ball with respesct to ground - acceleration of the liftOr, aball(lift) = g - a = 9.8 m/s^2 - a = 32 ft./s^2 - a [ 9.8m = 32 ft. ]displacement s = 6 ft.time taken t = 1 s.initial velocity u = 0s = ut + 1/2 at^2 = 0*1 + 1/2 (32-a)*1*1 = 1/2 (32-a)Therefore, 6 = 1/2 (32-a)Hence a = 20 ft./s^2

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Answer 2

an elevator is falling freely.a person inside the elevator takes a coin out and release it from rest.what will he observed