7. An object is at temperature of 4000C. At what
temperature would it radiate energy twice as fast?
(assume surrounding temperature negligible)
Answers
Answered by
0
Answer:From Stefan-boltzman law E
b
=5.67×(
100
T
)
4
So applying E
1
=2E
2
5.67×(
100
T
)
4
=2×5.67×(
100
673
)
4
T=800.33K
Explanation:
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