Question

7. An object is at temperature of 4000C. At what
temperature would it radiate energy twice as fast?
(assume surrounding temperature negligible)​

Answer 1

Answer:From Stefan-boltzman law E

b

​

=5.67×(

100

T

​

)

4

So applying E

1

​

=2E

2

​

5.67×(

100

T

​

)

4

=2×5.67×(

100

673

​

)

4

T=800.33K

Explanation: