Question

-7. An oblong park, 200 m long and 130 m
wide has two cross roads in its centre, and
each road is 3 m wide. Find the cost of
watering the park at the rate of 50 paise
per square metre.​

Answer 1

$\underline\bold{ Question}$

An oblong park, 200 m long and 130 m

wide has two cross roads in its centre, and

each road is 3 m wide. Find the cost of

watering the park at the rate of 50 paise

per square metre.

$\huge\mathfrak\pink{Answer}$

Step-by-step explanation:

The area of the road across the garden is

[(3 × 180) + (4 × 200) - (4 × 3)]

= 1328 sq. meters.

Now, the area of the full rectangle with sides

200 m and 180 m is (200 × 180) = 36000 sq. meters.

Therefore, the area of the garden is

(36000 - 1328) = 34672 sq. meters.

Now, the cost of watering the garden is 30 paisa per sq. meters i.e. 0.3 Rs. per sq, meters.

$<marquee>Therefore, the total cost of watering the garden</marquee>$

will be = (34672 × 0.3)

= 10401.6 Rs.

hope it's helpful for you .

$\huge\mathfrak\purple{thanks .}$