Question

7.An urn A contains 8 black balls and 5 white balls.A second urn B contains 6 black and 7 white balls. The probability that a blind folded person in one draw shall obtain a white ball a) 5/13 b) 7/13 c) 6/13 d) 5/26


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Answer 1

Answer

Urn 1: 8B+5W=13 balls

Urn 2: 6B+7W=13 balls

Selection of an urn is= 1/2

Probability that the one drawn ball is white= 1/2

[ 5/13+7/13 ]= 6/13