Question

7 and 12/40 minus 3 and 16/40 with solution

Answer 1

Answer:

$7 \times \frac{12}{40} - 3 \times \frac{16}{40} \\ \frac{292}{40} - \frac{136}{40} \\ \frac{292 - 136}{40} \\ \frac{156}{40} \\ \frac{39}{10}$

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