Math, asked by dhairyasharma3054, 9 months ago

7. Anil went from place A to B and then to place
C. A is 9.5 km from B and B is 13.47 km from C.
Dravid went from place A to D and from there to
place C. D is 7.82 km from A and C is 15.52 km
from D. Who travelled more and by how much?
A
9.5 km
7.82km
B
D
15.52 km
13.47 km​

Answers

Answered by Slogman
11

Total distance travelled by Dinesh = AB + BC

= 7.5 km + 12.7 km

= 20.2 km

Total distance travelled by Ayub = AD + DC

= 9.3km + 11.8 km

= 21.1 km

Hence, Ayub travelled More distance than Ayub as 21.1 > 20.2

The difference between path travelled by them

= 21.1km - 20.2 km

= 0.9 km

Hence, Ayub travelled 0.9 km more than Dinesh.

Hope it helps you.

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