Question

7.
Assuming that the potential energy of hydrogen atom in its ground state is zero. Then its energy in
the first excited state will be
(A) 13.6eV
(B) 27.2eV
(C) 23.8eV
(D) 10.2eV
8
The energy of the second Bohr orbit in the hydrogen atom is - 3.41 eV. The energy of the second
Bohr orbit of He ion would be
(A) - 0.85eV
(B) - 13.64eV
(C) -1.70eV
(D) -6.82eV
Which of the following is not a permissible value of angular momentum of electron in H-atom?
(A)
(B) 0.5
(C) 0.75 h (D) 1.5​

Answer 1

Answer:

Explanation:

since energy difference between first excited state and ground state is 10.2 electron volts for hydrogen atom and if ground state has energy zero then excited state has energy equivalent to 10.2 electron volt so as to compensate delta energy to be 10.2ev

Mathematically

Delta E (from n=1 to 2) in hydrogen atom = E(2)-E(1)

so,

10.2=E(2)-0

E(2)=10.2ev