Question

7. At 37°C and 0.1 atm, the mass density of
phosphorous vapour is 0.5 g/L. The molecular
formula of phosphorus is take R = 0.08
atm L
mol K.
(1) P
(2) P
(3) P₃
(4) PA​

Answer 1

Answer:

3 is the correct answer

Answer 2

*CORRECT QUESTION

At 37°C and 0.1 atm, the mass density of

phosphorous vapour is 0.5 g/L. The molecular

formula of phosphorus is take R = 0.08 atm L mol K.

(1) P

(2) P₂

(3) P₃

(4) P₄

ANSWER

The answer is P₄

GIVEN

At 37°C and 0.1 atm, the mass density of

phosphorous vapour is 0.5 g/L. The molecular

formula of phosphorus is take R = 0.08 atm L mol K.

TO FIND

Molecular formula of Phosphorus.

SOLUTION

We can simply solve the above problem as follows;

Temperature = 37 = 273 + 37 = 310 k

Pressure = 0.1 atm

Volume = density/mass = 31/0.05

PV = nRT

0.1 × (31/0.05) = n × 0.08 × 310

n = 4

Moles of Phosphorus = 4.

Molecular formula = P₄

Hence, The answer is P₄

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