Question

7. B is 200% efficient than A and 50% efficient than C, If all of them work together for 2 days to complete
the work, then in how many days A alone can complete the work?

Answer 1

Gɪᴠᴇɴ :-

• B is 200% efficient than A.
• B 50% efficient than C.
• All of them work together for 2 days to complete
• the work.

Tᴏ Fɪɴᴅ :-

• in how many days A alone can complete the work ?

Sᴏʟᴜᴛɪᴏɴ :-

Given That, B is 200% efficient than A. .

So, we can conclude That :- B is Two Times Efficient than A.

or,

→ A : B = 1 : 2

Also, we have given That, B 50% efficient than C.

So,

→ B : C = 2 : 4

Hence,

→ A : B : C = 1 : 2 : 4 (Efficiency Ratio) .

Therefore,

→ (A + B + C) per day work = 4 + 2 + 1 = 7 units.

→ work complete in 2 Days = 7 * 2 = 14 units = Total work.

Now,

→ Whole work complete by A alone = (Total work) / (Efficiency of A) = 14/1 = 14 Days . (Ans.)

Hence, A alone can complete the work in 14 Days.