7) Balance the folloviing Redox reaction.
a) H2O2+ Fe2+ gives Fe3+ + H20 (Acidic medium)
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Explanation:
Following the steps as in part (A), we have the oxidation half reaction equation as:-
Fe2+(aq)→ Fe3+(aq) + e-
And the reduction half reaction as:-
H2O2(aq) + 2H+(aq) + 2e-→ 2H2O
Multiplying the oxidation half reaction by 2 and then adding it to the reduction half reaction, we have the net balanced redox reaction as:-
H2O2(aq) + 2Fe2+(aq) + 2H+(aq)→ 2 Fe3+(aq) + 2H2O
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