Question

7 balls are drawn from a bag that contains 8 green and 6 white balls in how many ways 3 green and 4 white balls can be drawn

Answer 1

Answer:

35/143

let me know if this is correct

Answer 2

$A \: bag \: contains :\\Green \:balls = 8,\\White \:balls = 6$

$Number \: of \: ways \: 3 \: green \:and \\4 \: white \: balls\: can \:be \:drawn \\= ^{8}C_{3} \times = ^{6}C_{4}$

$\boxed { \pink { ^{n}C_{r} = \frac{n!}{(n-r)! r! }}}$

$= \frac{8!}{(8-3)! 3! } \times \frac{6!}{(6-4)! 4! }$

$= \frac{8\times 7 \times 6\times 5!}{5! \times 6} \times \frac{6\times 5 \times 4!}{2! \times 4!}$

$=</p><p>\frac{8\times 7 \times 6}{ 6} \times \frac{6\times 5 }{2}$

$= 8\times 7 \times 3\times 5 \\= 840$

Therefore.,

$\red { Number \: of \: ways \: 3 \: green \:and}$

$\red {4 \: white \: balls\: can \:be \:drawn }$

$\green { = 840 }$

•••♪