Question

7. By selling two transistors for 600 each, a shopkeeper gains 20 percent on one
transistor and loses 20 percent on the other.
Find : () C.P. of each transistor.
(ii) total C.P. and total S.P. of both the transistors.
(III) profit or loss percent on the whole.​

Answer 1

Answer:

no profit or no loss because both are 20 20

Answer 2

Answer:

Let CP

1 & CP 2

be the cost price of 1 transistors and 2

nd

transistors respectively

selling price of each transistors, SP

1=RS600

Gain of one transistors = 20%⇒ CP 1 SP1−CP 1×100=20.⇒

CP

1

600−CP

1

×100=20.

⇒600−CP

1

=

100

20

CP

1

⇒600=

100

20

CP

1

+CP

1

⇒

100

120

CP

1

=600

⇒CP

1

=

120

600×100

⇒CP

1

=Rs500

and loss of other transistors = 20 %

⇒

CP

1

CP

2

−SP

1

×100=20

⇒CP

2

−600=

100

20

CP

2

⇒CP

2

100

−20

CP

2

=600

⇒

100

80

CP

2

=600

⇒CP

2

=

80

600×100

=RS 750

cost price of 1

st

transistors = Rs 1350

Cost price of 2

nd

transistors = Rs 750.

Total cost price ,CP = Rs (600+750) = 1350

Total selling price SP = Rs (600+600) = Rs 1200.

loss on the whole =

CP

CP−SP

×100

1350

1350−1200

×100

1350

150

×100

= 11.11 % (approx.)