Physics, asked by saritalade1221, 5 months ago

7) Calculate the average molecular kinetic energy
1.per kmol 2. per k gram of oxygen at
27°C (R= 8.320 J/kmol avagodoos no. -
6.03 x 10^23 molecules /k mol​

Answers

Answered by tasneemthegirl
4

Answer:

ANSWER

(a) KE=

2N

3RT

, where R=8320J/Kmole, T=27+273=300K and N= Avogadro number =6.03×10

26

molecules/Kmole

or, KE=

2(6.03×10

26

)

3(8320)300

=

(0.67×10

24

)

(4160)

=62×10

−22

J/molecule

(b) K.E.=(

2

3

)kT

or, K.E.=(

2

3

)(1.38×10

−23

J/K)(27+273)K=6.21×10

−21

J/molecule.

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