7. Conner and Jana are multiplying (356)(39610).
Conner's Work
(3'56'8)(3'96'10) = 3'5 +'9 6'8 + '10 = 3'146'18
Jana's Work
(3'56'8)(3'96'10) = 3'5×'9 6'8×'10 = 3'45 6'80
Is either of them correct? Explain your reasoning.
when I add a ' it means the number right next to it is like "fifth power"
Answers
Step-by-step explanation:
GiveN:-
A father is 7 times as old as his son, two years ago the Father was 13 times as old as his son.
To FinD:-
The present age of son.
SolutioN:-
Let the present age of the son be x years.
Let the present age of the father be 7x years.
2 years ago their ages were:-
Son = (x - 2) years.
Father = (7x - 2) years.
It is said that two years ago the Father was 13 times as old as his son.
According to the question,
\large\implies{\sf{7x-2=13(x-2)}}⟹7x−2=13(x−2)
\large\implies{\sf{7x-2=13x-26}}⟹7x−2=13x−26
\large\implies{\sf{-2+26=13x-7x}}⟹−2+26=13x−7x
\large\implies{\sf{24=6x}}⟹24=6x
\large\implies{\sf{\dfrac{24}{6}=x}}⟹
6
24
=x
\large\implies{\sf{\dfrac{\cancel{24}}{\cancel{6}}=x}}⟹
6
24
=x
\large\implies{\sf{4=x}}⟹4=x
\large\therefore\boxed{\bf{x=4.}}∴
x=4.
Their present ages:-
Son's age = x = 4 years.
Father's age = 7x = 7 × 4 = 28 years.
The present age of the son is 4 years.