7 consecutive integers are 8 and the sum of the smallest 3 is 33 what is the sum of the largest three
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n-1, n, and n+1. These sum to 3n.
Therefore, 3n = 33 or n = 11
So n-1 = 10 and n+1 = 12
Our three numbers are: 10, 11, 12.
Therefore, 3n = 33 or n = 11
So n-1 = 10 and n+1 = 12
Our three numbers are: 10, 11, 12.
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