7. Construct a APQR in which ZP = 60° and 2Q = 45° and PQ = 4.8 cm. Write construction steps also.
Answers
Answer:
Steps of Construction:
1. Draw AB of length 6.5 cm
2. Taking A as centre and radius 7.2 cm, draw an arc
3. Taking B as centre and radius 8.4 cm, draw another arc to cut the first arc at point C
4. Now, join AC and BC
Hence,
Triangle ABC is the required triangle
(ii) PQ = 4.8 cm, QR = 6.3 cm and PR = 5.5 cm
Answer:
Draw the base QR = 6 cm.
At point Q draw a ray QX making an ∠ QXR = 60
o
.
Here, PR-PQ = 2cm
PR > PQ
The side containing the base angle Q is less than third side.
2) Cut the line segment QS equal to PR-PQ = 2 cm, from the ray QX extended on opposite side of base QR.
3) Join SR and draw its perpendicular bisector ray AB which intersect SR at M.
4) Let P be the intersection point of SX and perpendicular bisector AB. Then join PR.
Thus, △ PQR is the required triangle.