Question

7. Construct a quadrilateral CDEF in which CD = 3.5 cm, DE = 5 cm, EF = 4.6 cm, ZC = 125° and
angleD = 60°​

Answer 1

Step-by-step explanation:

Steps of Construction:

(i) Construct a line segment AB = 3.5 cm.

(ii) Taking A as centre and 4 cm radius construct and arc and with B as centre and 5.4 cm construct an arc which meets the previous arc at the point D.

Now join AD and BD.

(iii) Taking B as centre and 5 cm radius, construct an arc

Taking D as centre and 5.6 cm radius, construct an arc which meets the previous arc at the point C.

(iv) Join BC and CD.

Hence, ABCD is the required quadrilateral.

Answer 2

Step-by-step explanation:

1) Draw DE=5cm

2)At D Draw angle CDE = 60°

3)With D as centre & radius CD=3.5cm draw an arc at C

4)At C draw angle FCD = 120°

5)With E as centre & radius EF=4.6cm draw an arc at F

6) Now join CF and EF

Thus Required Quadrilateral Is formed

Hope This helps you Mate <3