Question

7. Denominator of a number is 4 less than it's numerator. If 6 is added to numerator, it becomes thrice
the denominator. Find the fraction​

Answer 1

Answer:

The required fraction is 9/5

Step-by-step explanation:

Given :

• Denominator of a number is 4 less than it's numerator.
• If 6 is added to numerator, it becomes thrice  the denominator.

To find :

the fraction

Solution :

 Let the numerator of the fraction be x

The denominator is 4 less than the numerator

Hence, denominator = x - 4

$\underline{\boxed{\sf fraction=\dfrac{numerator}{denominator}}}$

The fraction =  $\sf \dfrac{x}{x-4}$

Now,

6 is added to the numerator.

 New numerator = x + 6

the new numerator becomes thrice the denominator.

 x + 6 = 3(x - 4)

 x + 6 = 3x - 12

3x - x = 6 + 12

 2x = 18

  x = 18/2

   x = 9

The numerator of the required fraction = 9

The denominator = 9 - 4 = 5

Therefore, the fraction = 9/5

Verification :

If 6 is added to the numerator, then we get

9 + 6 = 15

Condition : 6 is added to numerator, it becomes thrice  the denominator.

  15 = 3 × 5

  15 = 15

 LHS = RHS

Hence verified!

Answer 2

Step-by-step explanation:

$\huge\sf\underline\green{answer}$

$\huge\sf\underline\blue{given,}$

1) denominator of a number is 4 less than its numerator.

2) if 6 is added to number it becomes thrice.

$\huge\sf\underline\red{to find}$

fraction.

$\huge\fcolorbox{black}{pink}{solution}$

let the numerator be 'x'

according to question,

denominater = x - 4

x + 6 = 3(x - 4)

x + 6 = 3x - 12

6+12 = 3x - x

18 = 2x

x = 18/2

x = 9

.: numerator = 9

denominater = 9 - 4 = 5

.: denominater = 5.

.: the fraction = 9/5