7. Determine the AP whose third term
is 15 and seventh term is 23.
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Answer:
AP: 11; 13; 15 ; 17;........23
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The required AP is 4 ,10 ,16 ,22 ,28 ,34 ,40......
Step-by-step explanation:
Let a be the first term,a3 be the third term, a5 be the fifth term and a7 be the seventh term
we know that : an=a+(n-1) *d
a3 = 16 [given]
a+(3-1)*d=16
a+2d=16...........(I)
Now a7-a5=12 [given]
[a+(7-1)d] -[a+(5-1)d] =12
2d=12
d=12/2
d=6
From eq. (1) we get,
a+2(6) =16
a+12=16
a=16-12
a=4
so, first term, a is 4
we can find AP by adding d continuously
so, the required AP is 4 , 16 , 22 , 28 , 34 , 40......
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