Question

7. Dinesh went from place A to place B and from
there to place C. A is 7.5 km from B and B is A
12.7 km from C. Ayub went from place A to place
D and from there to place C. Dis 9.3 km from A
and C is 11.8 km from D. Who travelled more
and by how much?​

Answer 1

Answer:

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Step-by-step explanation:

1st answer is in short and 2nd is in detail. U can refer any

Total distance travelled by Dinesh = AB + BC   =  7.5km + 12.7km  = 20.2 km  

Total distance travelled by Ayub = AD + DC = 9.3km + 11.8 km =  21.1 km  

Hence Ayub travelled More distance than Ayub as 21.1 > 20.2

The difference between path travelled by them = 21.1km - 20.2 km = 0.9 km.

Hence Ayub travelled 0.9 km more than Dinesh.

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For Dinesh

The distance between place A and place B = 7.5 km

The distance between place B and place C = 12.7 km

∴ The distance between place A and place C

= Distance between place A and place B + Distance between place B and place C

= 7.5 km + 12.7 km

= 20.2 km

∴ Distance travelled by Dinesh = 20.2 km

For Ayub

The distance between place A and placeD = 9.3 km

The distance between placeD and place C = 11.8 km

∴ The distance between place A and place C

= Distance between place A and place D + Distance between place D and place C

= 9.3 km + 11.8 km

= 21.1 km

∴ Distance travelled by Ayub = 21.1 km

∴ 21.1 > 20.2

So, Ayub travelled more by (21.1km – 20.2 km)

= 0.9km