7. Dinesh went from place A to place B and from
there to place C. A is 7.5 km from B and B is A
12.7 km from C. Ayub went from place A to place
D and from there to place C. Dis 9.3 km from A
and C is 11.8 km from D. Who travelled more
and by how much?
Answers
Answer:
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Step-by-step explanation:
1st answer is in short and 2nd is in detail. U can refer any
Total distance travelled by Dinesh = AB + BC = 7.5km + 12.7km = 20.2 km
Total distance travelled by Ayub = AD + DC = 9.3km + 11.8 km = 21.1 km
Hence Ayub travelled More distance than Ayub as 21.1 > 20.2
The difference between path travelled by them = 21.1km - 20.2 km = 0.9 km.
Hence Ayub travelled 0.9 km more than Dinesh.
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For Dinesh
The distance between place A and place B = 7.5 km
The distance between place B and place C = 12.7 km
∴ The distance between place A and place C
= Distance between place A and place B + Distance between place B and place C
= 7.5 km + 12.7 km
= 20.2 km
∴ Distance travelled by Dinesh = 20.2 km
For Ayub
The distance between place A and placeD = 9.3 km
The distance between placeD and place C = 11.8 km
∴ The distance between place A and place C
= Distance between place A and place D + Distance between place D and place C
= 9.3 km + 11.8 km
= 21.1 km
∴ Distance travelled by Ayub = 21.1 km
∴ 21.1 > 20.2
So, Ayub travelled more by (21.1km – 20.2 km)
= 0.9km
