Social Sciences, asked by vaijanthimala456, 6 months ago

7. Dinesh went from place to place B and from
there to place C. A is 7.5 km from B and Bis
12.7 km from C. Ayub went from place A to place
D and from there to place C. Dis 9.3 km from A
0) 21.37
and Cis 11.8 km from D. Who travelled more
and by how much?
8. Shyama bought 5 kg 300 g apples and 3 kg, 250g, avanveres, s
oranges and 4 kg 150 g bananas, Who bought more fruits
9. How much less is 28 km than 42.6 km?
2.6 MULTIPLICATION OF DECIMAL NUME​

Answers

Answered by keerthanareddy47
1

Explanation:

7.Distance travelled by Ayub = AD + DC = 9.3+11.8=21.1

Ayub travelled more than Dinesh .

difference=21.1-19.5=1.6

He travelled 1.6 km more than Dinesh

8.

Given, Shyama bought 5kg 300g =5,300 g apples and 3kg 250g =3,250 g mangoes. 

Total fruit bought by Shyam is 5,300+3,250=8,550g.......(1).

Also given, Sarala bought 4kg 800g =4,800g oranges and 4kg 150g =4,150g bananas.

So total fruit bought by Sarala is 4,800+4,150=8,950 g.......(2).

Since 8,950>8,550 so Sarala bought more fruit than Shyam.

9.

We can find it by getting the difference between these two.

Difference =42.6−28=14.6=42.6-28=14.6 km

So, 2828 km is 14.614.6 km less than 42.642.6 km.

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