Question

7. Divide 24x^3y+20x^2y^2-4xy by 2xy.

Answer 1

Q . Divide 24x³y + 20x²y² - 4xy by 2xy.


= ( 24x³y + 20x²y² - 4xy ) ÷ 2xy

= 2xy ( 12x² + 10xy - 2 ) ÷ 2xy

= ( 12x² + 10xy - 2 )

The required answer is ( 12x² + 10xy - 2 ).

Answer 2

Heya friend,
Here is it :

$24x^{3}$ y + $20 x^{2}$ $y^{2}$ - 4xy / 2xy

Taking 2xy common in the given set of numbers, we get,

2xy  ($12x^{2}$ + 10xy - 2) / 2xy 

By cancelling 2xy from numerator and denominator, we get the answer as :-

 $12x^{2}$ + 10xy - 2

Thanks!!!
@ MANAV