Question

7. Draw five triangles and measure their sides. Check in each case, if the sum of
the lengths of any two sides is always less than the third side​

Answer 1

$\huge{\sf{\underline{\orange{\boxed{Solution:-}}}}}$

$\large\red{\underline{\pink{\rm\: Triangle A. :-}}}$

• ac + ab is larger than bc
• ac + bc is larger than ab
• ab + bc is larger than ac

hence, proved that sum of any two sides are always larger than third side.

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$\large\red{\underline{\pink{\rm\: Triangle B. :-}}}$

• de + fe is larger than df
• df + fe is larger than de
• df + de is larger than fe

hence, proved that sum of any two sides are larger than third side.

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$\large\red{\underline{\pink{\rm\: Triangle C. :-}}}$

• gh + gi is larger than hi
• hi + gi is larger than gh
• hi + gh is larger than gi

hence, proved that sum of any two sides are larger than third side.

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$\large\red{\underline{\pink{\rm\: Triangle D.:-}}}$

• jk + kl is larger than jl
• jk + jl is larger than kl
• jl + kl is larger than jk

hence, proved that sum of any two sides are larger than third side.

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$\large\red{\underline{\pink{\rm\: Triangle E. :-}}}$

• mn + mo is larger than no
• mn + no is larger than mo
• mo + no is larger than mn

hence , proved that sum of any two sides are larger than third side.

$\huge{\sf{\underline{\orange{\boxed{Thank you:}}}}}$