Question

7. Draw parts of triangles one of the
some basic
or equal bases) and
detween the same
parellels on the
as shown
graph sheet
​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Triangle on same base and between same parallels is equal in area.

In the adjoining figure, ∆ABD and ∆DEF are having equal base ‘a cm’ and are between the same parallels BF and AD.

Triangle on Same Base and between Same Parallels

Therefore, area of ∆ABD = Area of ∆DEF

Prove that the triangles on same base and between same parallels are equal in area.

 

Let ∆ABC and ∆ABD be on the same base AB and between the same parallel AB and CD. It is require to prove that ∆ABC = ∆ABD.

Construction: A parallelogram ABPQ is constructed with AB as base and lying between the same parallels AB and CD.

Triangles on Same Base and between Same Parallels

Proof: Since ∆ABC and parallelogram ABPQ are on the same base AB and between the same parallels AB and Q,

Therefore, ∆ABC = ½(Parallelogram ABPQ)

Similarly, ∆ABD = ½(Parallelogram ABPQ)

Therefore, ∆ABC = ∆ABD.