Question

7] Equation to the straight line cutting off an
intercept 2 from the negative direction of the axis of y and inclined at 30° to the positive direction of axis of x, is
a) y + x-√3=0 b)y-x+2=0.
c) y - √3x - 2 = 0 d) √3y - x + 2/3 = 0​

Answer 1

Answer:

option(d)

Step-by-step explanation:

c=-2

m=tan 30=1/√3

eqn of line

y=mx+c

y=x/√3 -2

√3y=x-2√3

√3y-x+2√3=0

option(d)

Answer 2

Hey MATE!

Since the line passes through the point (0,-2) [as given in question that it makes intercept with negative y axis at 2].

Therefore (0,-2) should satisfy the equation of the line.

Since we can observe from the options that only (2) option satisfies the given condition, therefore the equation of the line is y-x +2 = 0.

Proof:

x = 0 ,y = -2

-2 -0 + 2 =0

Hence proved

Hope it helps

HAKUNA MATATA :))