Question

7) factor of x²+ 10x+25 is?​

Answer 1

Answer:

x=-5

Step-by-step explanation:

Considering the equation as ax^2+bx+c=0

where a,b,c are constants

To factorise the equation, b should be divided in 2 parts b1 and b2 such a way that b1*b2=a*c and b1+b2=b.

Thus, x^2+10x+25=0

Comparing with its general equation, a=1, b=10 and c=25.

b1*b2=1*25=25 and b1+b2=10

So,

X^2+5x+5x+25=0

x(x+5)+5(x+50)=0

(x+5)*(x+5)=0

(x+5)^2=0

x+5=0

x=-5

Answer 2

• As per the data given in the question, we have to find the value of the expression.

        Given data:- $x^{2} +10x+25.$

        To find:- Value of the expression.

        Solution:-

• We know that factorization means reducing any algebraic or quadratic equation.

• steps to solve quadratic equations,

          Step 1: Rearrange the given quadratic so that is it equal to zero.

          Step 2: Factorise the quadratic.

          Step 3: Form two linear equations.

          Step 4: Solve the equations to find the roots of the equation.

       Therefore,

        $\Rightarrow x^{2}+10 x+25 \\\Rightarrow x^{2}+5 x+5 x+25\\\Rightarrow x(x+5)+5(x+5) \\\Rightarrow (x+5)(x+5)\\\Rightarrow (x+5)^{2}.$

      Hence we will get the Factor value $(x+5)(x+5).$