Question

7. Factorise : 4(2a-b)(3c-4d) + 7(2a- b)(c-d)
give full answer​

Answer 1

Answer:

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✯ 4(2a-b)(3c-4d) + 7(2a- b)(c-d)

= 4 ( 6ac - 8ad - 3bc + 4bd ) + 7 ( 2ac - 2ad - bc + bd )

= 24ac - 32ad - 12bc + 16bd + 14ac - 14 ad - 7bc + 7bd

= 24ac + 14ac - 32ad - 14ad - 12bc - 7bc + 16bd + 7bd

= 38ac - 46ad - 19bc + 23bd

= 2a ( 19c - 23d ) - 1b ( 19bc - 23d )

= ( 19c - 23d )( 2a - b )

Answer 2

Step-by-step explanation:

4(2a-b)(3c-4d) + 7(2a- b)(c-d)

= 4 ( 6ac - 8ad - 3bc + 4bd ) + 7 ( 2ac - 2ad - bc + bd )

= 24ac - 32ad - 12bc + 16bd + 14ac - 14 ad - 7bc + 7bd

= 24ac + 14ac - 32ad - 14ad - 12bc - 7bc + 16bd + 7bd

= 38ac - 46ad - 19bc + 23bd

= 2a ( 19c - 23d ) - 1b ( 19bc - 23d )

= ( 19c - 23d )( 2a - b )