7. Factorize: 10a² - 15 b² + 20c²
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Answered by
0
Answer:
5(2a
2
−3b
2
+4c
2
)
We have, 10a
2
=2×5×a×a,
15b
2
=3×5×b×b
and,20c
2
=2×2×5×c×c
The three terms have 5 as a common factor
10a
2
−15b
2
+20c
2
=(2×5×a×a)−(3×5×b×b)+(2×2×5×c×c)
=5×(2×a×a−3×b×b+4×c×c)
=5(2a
2
−3b
2
+4c
2
)
Answered by
0
Answer:
We have, 10a^2 = 2 × 5 × a × a, 15b^2 = 3 × 5 × b × b and, 20c^2 = 2 × 2 × 5 × c × c The three terms have 5 as a common factor 10a^2 - 15b^2 + ... More
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