Question

7. Factorize: 10a² - 15 b² + 20c²​

Answer 1

Answer:

5(2a

2

−3b

2

+4c

2

)

We have, 10a

2

=2×5×a×a,

15b

2

=3×5×b×b

and,20c

2

=2×2×5×c×c

The three terms have 5 as a common factor

10a

2

−15b

2

+20c

2

=(2×5×a×a)−(3×5×b×b)+(2×2×5×c×c)

=5×(2×a×a−3×b×b+4×c×c)

=5(2a

2

−3b

2

+4c

2

)

Answer 2

Answer:

We have, 10a^2 = 2 × 5 × a × a, 15b^2 = 3 × 5 × b × b and, 20c^2 = 2 × 2 × 5 × c × c The three terms have 5 as a common factor 10a^2 - 15b^2 + ... More