Question

7. Find k so that the quadratic equation (k+1)x 2- 2(k+1)x+1=0 has equal roots.

Answer 1

Answer:

k = 0, k =-7

Step-by-step explanation:

For any quadratic equation to have equal roots

D= 0

D= $b^{2} -4ac$

here, a= (k+1) , b = -2(k+1), c = 1

0 = (-2(k+1))^2 - 4(1)(k+1)

0 = 4k^2+4+ 32k -4k-4

0= 4k^2+28k

0 = k^2 +7k

k = 0, k =-7

Answer 2

Answer:

k=0, k = - 7 .

Step-by-step explanation:

For any quadratic equation to have equal roots

D= 0

D= b^{2} - 4ac

here, a= (k+1) , b = -2(k+1), c = 1

0 = (-2(k+1))^2 - 4(1)(k+1)

0 = 4k^2+4+ 32k -4k-4

0= 4k^2+28k

0 = k^2 +7k

k = 0, k =-7

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