7. find P(E/F) when Two coins are tossed once, where
(i) E: tail appears on one coin,
(ii) E: no tail appears,
F: one coin shows head
F: no head appears
Answers
Answered by
0
Answer:
Both
Step-by-step explanation:
As it depends upon the coin, when we flip the coin both the situtaion may lead as it can show heads and tail too, so here i conclude by giving the answer both....
Thank you....
Answered by
0
Answer:
(i)Ans=3/4
(iilAns=1/4
(iii)Ans=3/4
(iv)Ans=1/4
Step-by-step explanation:
Here total conditions will be four
i.e.(HH,HT,TH,TT) Where H is Heads and T is tails
n(S)=4
Let A be condition (i)
(A)=(HT,TH,TT)
n(A)=3
p(A)=n(A)/n(S)
=3/4
LetB be condition (ii)
(B)=(HH)
n(B)= 1
p(B)=n(B)/n(S)
=1/4
Same with condition (iii)&(iv)
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