Math, asked by deepanshiJain, 7 months ago

7. find P(E/F) when Two coins are tossed once, where
(i) E: tail appears on one coin,
(ii) E: no tail appears,
F: one coin shows head
F: no head appears​

Answers

Answered by Iloo
0

Answer:

Both

Step-by-step explanation:

As it depends upon the coin, when we flip the coin both the situtaion may lead as it can show heads and tail too, so here i conclude by giving the answer both....

Thank you....

Answered by atharvsgujare000
0

Answer:

(i)Ans=3/4

(iilAns=1/4

(iii)Ans=3/4

(iv)Ans=1/4

Step-by-step explanation:

Here total conditions will be four

i.e.(HH,HT,TH,TT) Where H is Heads and T is tails

n(S)=4

Let A be condition (i)

(A)=(HT,TH,TT)

n(A)=3

p(A)=n(A)/n(S)

=3/4

LetB be condition (ii)

(B)=(HH)

n(B)= 1

p(B)=n(B)/n(S)

=1/4

Same with condition (iii)&(iv)

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