7. Find the 31-st term of an A.P whose 11th term is 38 and the
16th term is 73.
Answers
Answered by
6
Answer:
a+10d=38 *1
a+15d=73 *2
*2-*1 gives
5d=45
d=9
a+10d=38
a+90=38
a=-52
We want to find 31st term
a+30d=-52+270=218
Therefore your answer is 218
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Answered by
7
11th term of AP is 38 and,
16th term of AP is 73.
The 31st term of AP = ?
Let first term of AP be a
Let first term of AP be aand common difference be d
Let first term of AP be aand common difference be dNow,
And,
From eq (i) and eq (ii),
a + 10d = 38 ‿︵‿︵│
⠀ ⠀ ⠀ ⠀⠀⠀ ⠀ ⠀ ⠀⠀⠀ ⠀ |Subtracting
a 15d = 73 ‿︵‿︵│
-⠀ -⠀ ⠀ -
━━━━━━━━━━━━━━
-5d = -35
Now,
Substitute the value of d in equation (i),
Then,
Hence, the 31st term of an AP was
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