7 Find the area of an isosceles triangle having base
8 cm and length of one of the equal sides is 6 cm.
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Answer:
8√5 cm²
Step-by-step explanation:
In the figure AB=AC=6 cm
Draw a perpendicular AD from A to BC
Then D is mid point of BC
Thus BD=4 cm
In the ΔABD
AD= √(AB²-BD²)
=√36-16
=√20=2√5
Area of ΔABC
=BC*AD/2
=8*2√5/2
=8√5 cm²
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