Question

7.
Find the area of minor segment of a circle of
radius 6 cm when its chord subtends an angle
60° at its centre.
(3 = 1.73)
​

Answer 1

area of minor segment = πr^20/360 -1/2 r^2 sine

=22/7*6*6*60/360 - 1/2 *6*6'sin60°

=132/7-973

putting the value of ✓3=1.73

answer is 24.01 cm square