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Find the coordinate of the points on the parabola y2 = 8x whose focal distance is 10.
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Answer: Distance of point P(x,y) from the focus S(a,0) of the parabola y2=4ax is SP = a+x.
Also, given that SP=10.
∴ 10=2+x
∴ x=8
So, from y2=8x,
y2=64
∴ y=±8
So, coordinates of point P are (8,8) or (8,-8).
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