Question

7. Find the equation of the line passing through the points
i) (1,-2).(-2,3) ii) (2, -3), (0, -3) ill) (1, 2), (1, -2)
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Answer 1

Answer:

Step-by-step explanation:

(i)

(1,-2), (-2,3)

m = (y₂ - y₁)/(x₂ - x₁)

   = (3 + 2)/(-2 -1)

   = -5/3

Now,

y - y₁ = m(x - x₁)

=> y + 2 = -5/3(x - 1)

=> 5x + 3y + 1 = 0

(ii)

(2,-3), (0,-3)

m = (y₂ - y₁)/(x₂ - x₁)

   = (-3 + 3)/(0 - 2)

   = 0

Now,

y - y₁ = m(x - x₁)

=> y + 3 = 0(x - 2)

=> y + 3 = 0

(iii)

(1,2), (1,-2)

m = (y₂ - y₁)/(x₂ - x₁)

   = (-2 - 2)/(1 - 1)

   = 0

Now,

y - y₁ = m(x - x₁)

=> y - 2 = 0(x - 1)

=> y - 2 = 0

Hope it helps!