Question

7. Find the greatest number of four digits which is divisible by 15, 20 and 25.
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Answer 1

Answer:9900

Step-by-step explanation:The greatest number of four digits which is divisible by 15 20 and 25 is 9900. Step-by-step explanation: The greatest number of four digit is 9999. The L.C.M. of given numbers is 300.

Answer 2

➡ The greatest number of four digits which is divisible by 15, 20 , and 25 is 9990

$\large \green{ \bold{ \underline{step \: by \: step \: explaination : }}}$

➡ The greatest number of four digits is 9990

The factors of given numbers are

$\bullet \large \sf \: 15 \: = 3 \times 5$

$\bullet \large \sf \: 20 = 4 \times 5$

$\bullet \large \sf \: 25 = 5 \times 5$

The LCM of 15 ,20 and 25 is

$\large\sf{ LCM= 3 \times 4 \times 5 \times 5 =300}$

The LCM of a given numbers is 300 . It means greatest number of four digits which is divisible by 15,20 and 25 must be divisible by 300.

• Divide 9999 by 300

$\implies \large \sf \: \frac{9999}{300} = 33 + \frac{99}{300}$

The quotient is 33 and remainder is 99

$\implies \: 9999 - 99 = 9900$

Therefore, The greatest number of four digits which is divisible by 15,20,and 25 is 9900.