Question

7. Find the largest number that will divide 398,436 and 542 leaving remainders 7, 11, 15 respectively.

Answer 1

On dividing 398 by the required number, there is a remainder of 7. This means that 398 – 7 = 391 is exactly divisible by the required number. Similarly, 436 -11 = 425 and 542 – 15 = 527 are exactly divisible by the required number.

The HCF of two positive integers is the largest positive integer that divides both the integers.

So, the required number will be the HCF of 391, 425 and 527. And that can be found by using Euclid’s division algorithm.

425 = 391 x 1 + 34

391 = 34 x 11 + 17

34 = 17 x 2 + 0

Thus, HCF = 17

Hence, the required number is 17.

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Answer 2

nice question. here is your answer-first subtract  398-7 = 391, 436-11 = 425, 542-15 = 527. 
then we will find their hcf-
391= 17×23 
425=17×25 
527=17×31 
 hcf of 391, 425 and 527 is 17 
so now-
1. 391/17=23, but now with 398/17=23 is quotient and remainder is 7.
2. 425/17=25, but now with 436/17=25 is quotient and remainder is 11.3. 527/17=31, but now with 542 /17=31 is quotient and remainder is 15.Hope it helps.please mark as brainliest