Question

7. Find the lateral or curved
surface area of of a closed
cylindrical petrol tank whose
height is 7 m and diameter is
*
8m
276 m2​

Answer 1

Answer:

Diameter of the closed cylindrical petrol tank

= 8m

:. Radius =8/2=4m

Lateral or curved surface area of of a closed cylindrical petrol tank

= 2πrh

= {2×(22/7)×4×7} m²

= (2×22×4) m²

= 176m²

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Answer 2

Given :-

• Height of cylindrical tank = 7 m
• Diameter of cylindrical tank = 8 m
• Radius of cylindrical tank = Diameter/2 = 8/2 = 4 m

To Find :-

• Curved Surface Area of cylindrical tank = ?

Answer :-

• Curved Surface Area of cylindrical tank = 176 m²

Explaination :-

Let Radius be 'r' m and height be 'h' m.

★ According to Question now,

→ CSA of cylindrical tank = 2πrh

→ CSA of cylindrical tank = 2 × 22/7 × 4 × 7

→ CSA of cylindrical tank = 2 × 22 × 4

→ CSA of cylindrical tank = 176 m²

Therefore,Curved Surface Area of cylindrical tank is 176 m².

_____________________..

$\boxed{\bigstar{\sf \ Cylinder :- }}\\ \\\sf {\textcircled{\footnotesize1}} Volume \ of \ Cylinder= \pi r^2 h \\ \\ \\ \sf {\textcircled{\footnotesize2}}\ Curved \ surface\ Area \ of \ cylinder= 2\pi r h\\ \\ \\ \sf {\textcircled{\footnotesize3}} Total \ surface \ Area \ of \ cylinder= 2\pi r (h+r)$

$\boxed{\bigstar{\sf \ Cone :- }}\\ \\\sf {\textcircled{\footnotesize1}} Volume \ of \ Cone= \dfrac{1}{3}\pi r^2 h \\ \\ \\ \sf {\textcircled{\footnotesize2}}\ Curved \ surface\ Area \ of \ Cone = \pi r l \\ \\ \\ \sf {\textcircled{\footnotesize3}} Total \ surface \ Area \ of \ Cone = \pi r (l+r) \\ \\ \\ \sf {\textcircled{\footnotesize4}} Slant \ Height \ of \ cone (l)= \sqrt{r^2+h^2}$

$\boxed{\bigstar{\sf \ Hemisphere :- }}\\ \\\sf {\textcircled{\footnotesize1}} Volume \ of \ Hemisphere= \dfrac{2}{3}\pi r^3 \\ \\ \\ \sf {\textcircled{\footnotesize2}}\ Curved \ surface\ Area \ of \ Hemisphere = 2 \pi r^2 \\ \\ \\ \sf {\textcircled{\footnotesize3}} Total \ surface \ Area \ of \ Hemisphere = 3 \pi r^2$

$\boxed{\bigstar{\sf \ Sphere :- }}\\ \\\sf {\textcircled{\footnotesize1}} Volume \ of \ Sphere= \dfrac{4}{3}\pi r^3 \\ \\ \\ \sf {\textcircled{\footnotesize2}}\ Surface\ Area \ of \ Sphere = 4 \pi r^2$