Question

7. Find the length of a rectangle whose area is 120
sq cm and breadth is 8 cm.
​

Answer 1

Answer :- length = 15 cm

Answer 2

Step-by-step explanation:

Question :-

• Find the length of rectangle whose area is 120 cm² and breadth is 8 cm.

To Find :-

• Length of rectangle.

Solution :-

Given :

• Area = 120 cm²
• Breadth = 8 cm

By using the formula,

${\longrightarrow{\sf Area\ of\ rectangle\ =\ l \times b}}$

Where,

• l = length of the rectangle
• b = breadth of the rectangle

According to the question, by using the formula, we get :

${\longrightarrow{\sf Area\ of\ rectangle\ =\ l \times b}}$

${\longrightarrow{\sf 120\ =\ l \times 8}}$

${\longrightarrow{\sf 120\ =\ 8l}}$

${\longrightarrow{\sf \dfrac{120}{8}\ =\ l}}$

${\longrightarrow{\sf 15\ =\ l}}$

${\longrightarrow{\sf l\ =\ 15\ cm}}$

∴ Hence, length of rectangle is 15 cm.

More To Know :-

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$